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IBM C9050-042 Exam Syllabus Topics:
| Section | Objectives |
|---|---|
| Debugging and Optimization | - Debugging techniques
|
| File Handling and Data Management | - Sequential and indexed file processing
|
| Program Control and Logic | - Control statements
|
| IBM Enterprise PL/I Features | - Enterprise extensions
|
| PL/I Language Fundamentals | - Basic syntax and program structure
|
IBM Developing with IBM Enterprise PL/I Sample Questions:
A lead developer reviewing code from one of the programmers found the following code. What should the
programmer be told about BY NAME assignments?
DCLl STR1, 3FB15 FIXED BIN (15), 3 CH10 CHAR (10), 3 NAME CHAR (25). 3 ADDR CHAR (30), 3
FB31 FIXED BIN(31);
DCL 1 STR2, 3 FB31 FIXED BIN (31), 3 FB31B FIXED BIN (31), 3 NAME CHAR (20), 3 ADDR CHAR
(30), 3 CH20 CHAR (20);
STR2 = STR1, BY NAME;
- A. They are incorrect and should be replaced by individual assignments.
- B. They do not work in this case and the code should be replaced by individual assignments.
- C. There is nothing wrong with using BY NAME assignments in this situation.
- D. They can have inadvertent side effects and the code should be analwed.
Correct Answer: D 🗳️
A mainframe project is behind schedule and a project leader has only one copy of a PC-based PL/I
compiler available for distribution to team members who are all eager to use it. Optimally, to whom should
it be provided first?
- A. The person in the critical path
- B. The project leader and her manager
- C. The person who does the most PL/I development
- D. The person who makes the greatest demand
Correct Answer: A 🗳️
Which of the following may be an advantage of the BEGIN OPTIONS (INLINE) statement?
- A. The program uses less stack storage.
- B. The program uses less heap storage.
- C. The program runs faster because all variables declared inside the BEGIN block are already allocated
when the block containing the BEGINblock is entered. - D. The code runs faster because more variables will be optimized in the BEGINblock.
Correct Answer: C 🗳️
Which of the following structures will NOT contain padding bytes if the PL/I default for alignment is
applied?
- A. DCL 1 A, 2 B FLOAT DEC (16), 2 F FLOAT DEC (16), 2 E FIXED BIN (31), 2 C FIXED DEC (5,2), 2 D
CHAR (3); - B. DCL 1 A, 2 E FIXED BIN (31), 2 C FIXED DEC (5,2), 2 B FLOAT DEC (16), 2 F FLOAT DEC (16), 2 D
CHAR (3); - C. DCL 1 A, 2 B FLOAT DEC (16), 2 F FLOAT DEC (16), 2 C FIXED DEC (5,2), 2 E FIXED BIN (31), 2 D
CHAR (3); - D. DCL 1 A, 2 B FLOAT DEC (16), 2 C FLOAT DEC (5,2), 2 D CHAR (3), 2 E FIXED BIN (31), 2 F FLOAT
DEC (16);
Correct Answer: A 🗳️
What happens to AUTOMATIC variables when a procedure is called recursively?
- A. The values from the previous invocation are lost.
- B. The values from previous invocations are preserved but can be overwritten in the new invocation.
- C. The values from the previous invocation are saved and are available when the current invocation ends.
- D. The values from the previous invocation are saved and are available to the new invocation.
Correct Answer: C 🗳️
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