Exam HPE7-A01 Topic 9 Question 61 Discussion
Actual exam question for HP's HPE7-A01 exam
Question #: 61
Topic #: 9
Question #: 61
Topic #: 9
You are deploying a bonded 40 MHz wide channel What is the difference in the noise floor perceived by a client using this bonded channel as compared to an unbonded 20MHz wide channel?
Suggested Answer: B Vote an answer
The difference in the noise floor perceived by a client using a bonded 40 MHz wide channel as compared to an unbonded 20 MHz wide channel is 3 dB. The noise floor is the level of background noise in a given frequency band. When two adjacent channels are bonded, the noise floor increases by 3 dB because the bandwidth is doubled and more noise is captured. The other options are incorrect because they do not reflect the correct relationship between bandwidth and noise floor. References:
https://www.arubanetworks.com/techdocs/ArubaOS_86_Web_Help/Content/arubaos-solutions/wlan-rf/rf-fundam
https://www.arubanetworks.com/techdocs/ArubaOS_86_Web_Help/Content/arubaos-solutions/wlan-rf/rf-fundam
by Wythe at Oct 13, 2026, 01:46 AM
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