Exam JN0-106 Topic 5 Question 1 Discussion

In the IPv4 addressing architecture, a /24 prefix length (standard Class C subnet mask of 255.255.255.0) signifies that the first 24 bits of the 32-bit address are reserved for the network portion, leaving 8 bits for the host portion. To calculate the total number of available IP addresses within this range, the formula $2^n$ is applied, where $n$ represents the number of host bits. For a /24 mask, $2^8$ results in 256 total addresses.
However, standard networking conventions-which Junos OS adheres to for interface configuration and routing-require the reservation of two specific addresses within any given subnet. The first address in the range is the network address (where all host bits are 0), used to identify the subnet itself in the routing table.
The last address in the range is the directed broadcast address (where all host bits are 1), utilized to communicate with all hosts on that segment simultaneously. Therefore, the number of " usable " hosts that can be assigned to device interfaces, such as ge-0/0/0.0 or a workstation, is calculated as $2^n - 2$. In this instance, $256 - 2 = 254$. Understanding this calculation is fundamental for an architect when performing IP address management (IPAM) and ensuring that the Packet Forwarding Engine is configured with valid, assignable host addresses within a defined broadcast domain.
Reference: Networking Fundamentals, IPv4 Subnetting and CIDR.