Exam JavaScript-Developer-I Topic 4 Question 108 Discussion

The goal:
" Temporarily and quickly remove them. "
The fastest way is to run a script in the browser console that removes all such elements:
document.querySelectorAll( ' .ad-library-item ' ).forEach(el = > el.remove()); This immediately removes all 50+ elements and requires no page reload.
Option analysis:
* A & B : Preventing load events is unreliable and does not remove already-created DOM nodes.
* C : Correct-console code can remove all matching DOM elements instantly.
* D : Possible but extremely slow; removing 50+ elements one by one in the inspector is not "quick." Therefore, C is the best answer.
JavaScript Knowledge References (text-only)
* The browser console can run arbitrary JavaScript that manipulates the DOM.
* document.querySelectorAll() returns all matching DOM nodes.
* Nodes can be removed using .remove().