Exam JavaScript-Developer-I Topic 6 Question 133 Discussion
Actual exam question for Salesforce's JavaScript-Developer-I exam
Question #: 133
Topic #: 6
Question #: 133
Topic #: 6
Given the code below:
const delay = async delay =>{
return new Promise((resolve,reject)=>{
console.log(1);
setTimeout(resolve,deleay);
});
};
const callDelay = async ()=>{
console.log(2);
const yup = await delay(1000);
console.log(3);
}
console.log(4);
callDelay();
console.log(5);
What is logged to the console?
const delay = async delay =>{
return new Promise((resolve,reject)=>{
console.log(1);
setTimeout(resolve,deleay);
});
};
const callDelay = async ()=>{
console.log(2);
const yup = await delay(1000);
console.log(3);
}
console.log(4);
callDelay();
console.log(5);
What is logged to the console?
Suggested Answer:
4 2 1 5 3
by Bill at Jul 31, 2026, 10:15 AM
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